in a combo preamp such as trek ii uc-1a, where has a pilot lamp to be conencted to, in order to indicate active tremolo? In a Leslie 147, I think one can just install a pilot lamp between pins 2 and 3 of the 6 pin connector. How could this be done for a 122?
Greetings Christian
1958 B3, 1960 M3, 1953 M2 converted into M3, 2x Leslie 122, Ventilator II, Viscount Legend Solo
The preamps use neon lamps requiring a higher voltage (around 60V) which can be sourced from the incoming power. (mains) The original preamp for a 147 did connect lamp directly to the AC power (with resistor) for speed indication. Leslie didn't make a combo kit for the 122. Trek II's kit uses a DPDT switch for speed switching. That way, the indicator lamp wiring is kept separate from the lower voltage switching for the non-AC switched models.
If you're building a kit you will have mains power internally. Using a DPDT switch so one side can operate the lamp while the other side can operate the switching.
Well.....I live in germany and have a 110v Hammond M3 and a 110v Leslie 122. Normally I have a step down transformer (230->110v / 500 watts) before my rig. The Leslie gets powered from the organ via a Leslie 8010 kit. But now I want to buy a clonewheel and also use it with the leslie. For this I need a leslie preamp. As the trek ii uc-1a is not available here, i will buy a german preamp which uses 230v. Thus, there will be 230v on pins 3 and 4 of my leslie cable. I thought, in order to be able to use both setups, I could build a stepdown box:
230v 6-pin leslie input -> 230/110v stepdown-> 110v 6 pin leslie output. That should not be the problem. But I thought it would be nice to install a tremolo pilot lamp into that box. But I don't know how.
1958 B3, 1960 M3, 1953 M2 converted into M3, 2x Leslie 122, Ventilator II, Viscount Legend Solo
Typicaly the switching is as is :
The L122 send the B+ (~300V) to the preamp. The B+ is downed to a lower value and, after switching, return to the Leslie by the center tap of balanced signal transformer.
But there is not enough curent (~1mA) in this circuit to lit a bulb even not a led.
You will have to make some electronics to detect this current and amplify it to control a switch in a circuit where the power is sufficient to light a bulb.
Something like a sensitive relay.
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